Homework Help: coordinate geometry

Posted by Anonymous on Thursday, March 1, 2012 at 1:34pm.

Find the value of x such that PQ=QR where the coordinates of P,Q and R are [6,-1], [1,3]and[x,8] respectively

coordinate geometry - Steve, Thursday, March 1, 2012 at 3:59pm
PQ² = 5² + 4²
QR² = (x-1)² + 5^2

Looks like x-1 = 4 or x=5
coordinate geometry - PS - Steve, Thursday, March 1, 2012 at 4:00pm
or, x-1 = -4 making x=-3

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