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July 25, 2014

July 25, 2014

Posted by **allen** on Thursday, March 1, 2012 at 1:04pm.

- alebra -
**MathGuru**, Friday, March 2, 2012 at 5:48pmIf your problem is this:

(3m + n)/(4n^2m) + (3m + n + 5)/(4n^2m)

Then we have:

3m + n + 3m + n + 5

-------------------

4n^2m

Combine like terms:

6m + 2n + 5

-----------

4n^2m

I hope this helps and is what you were asking.

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