Posted by jenna on Thursday, March 1, 2012 at 9:47am.
1000 mL x 0.05M = 50 millimols.
x mL x 0.1M = ? mmols.
-----------------
............HOCl + OH^- ==> OCl^- + H2O
initial.....50......0........0........0
add.................x................
change......-x....-x.........x........x
equil.......50-x....0.........x........x
I used 3E-8 for Ka for HOCl
pH = pKa + log(base)/(acid)
8.00 = 7.52 + log(x)/(50-x)
Solve for x = millimols OH^- added. Then mL = mmols/M. I get approximately 380 mL
I believe you made a slight error in the last calculation from mmol --> mol. The answer should be around 3.8L.
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