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April 20, 2014

April 20, 2014

Posted by **Steven** on Thursday, March 1, 2012 at 9:41am.

1. find the equation

2. tell which conic section the graph will be.

- Math -
**Steve**, Thursday, March 1, 2012 at 3:20pmlooks like a parabola.

distance from (x,y) to x=6 is x-6

distance from (-2,4) given by (x+2)^2 + (y-4)^2

vertex at (4,4) since it is 2 from x=6 and 6 from (-2,4)

(3(x-6))^2 = (x+2)^2 + (y-4)^2

or

9(x-6)^2 - (x+2)^2 = (y-4)^2

Not sure how to reduce that to

(y-4) = a(x-4)^2

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