Posted by **Pam J.** on Thursday, March 1, 2012 at 8:19am.

The art department had a party at the teacher's house. There are 50 brownies and 40 celery sticks served as refreshments. Each art student had the same number of brownies and the same number of whole celery sticks, & nothing was left over. The art teacher didn't eat. What is the largest number of art members that might have been at the party?

- Can' t Figure Out: Math - HCF -
**MathMate**, Thursday, March 1, 2012 at 9:12am
Here we look for the highest number of members N. Since each member eats the same number of celery (c) and brownies (b), then

Nb=50 and Nc=40

We need to find the highest common (HCF) denominator of 50 and 40 to find N.

There are two ways to find the HCF.

The traditional way taught in schools is

to factorize the numbers and extract common factors. These factors are then multiplied to give the HCF.

50=**2*5***5

40=2*2***2*5**

So we see that the common factor is 2*5=10, which is the HCF.

The other way is using Euclid's algorithm, which is suited for mental calculations.

Take the difference between the two numbers, and repeat using the smaller number and the difference until the difference divides the smaller number.

50-40=10. Since 10 divides 40, 10 is the HCF.

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