Posted by **Tess** on Thursday, March 1, 2012 at 4:00am.

Expand using logarithm properties: log6 x(x+5)/x^6

I am so confused about this problem. Could anyone explain this to me?

- Math -
**Steve**, Thursday, March 1, 2012 at 11:56am
just as powers of products add (6^2 * 6^3 = 6^5) and subtract (6^8 / 6^3 = 6^5)

log of a product is the sum of the logs, and log of a quotient is difference of logs. That's because of the definition of log:

log_{6}N is the power of 6 needed to get N. Even though it looks weird, a log is just an exponent!

So, log x(x+5)/x^6

= logx + log(x+5) - log x^6

Now, log x^6 = log x*x*x*x*x*x = logx + logx + logx + logx + logx = 6logx

and now qwe end up with

logx + log(x+5) - 6logx

= log(x+5) - 5logx

That could also have been achieved by noticing that

x(x+5)/x^6 = (x+5)/x^5

notice how the power subtracted when factoring out the x?

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