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March 30, 2017

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The probability that at most 3 tosses of a balanced dice are required to get a prime number on top is equal to

a. 7/8, b.1/4, c. 1/2, d.3/4.

  • Probability and statistics - ,

    "at most 3" = three or less

    So the prime number can appear at least once in the three tosses, no matter which one(s).

    Prime numbers ≤6 are 2,3 and 5.
    So the outcome of each toss is either prime or not prime.

    The probability of getting a prime is 3 out of 6 possible events, or 3/6=1/2.

    We look for at least one success out of three tosses. Thus the only situation failure can occur is all three tosses are not-prime numbers, which has a probability of P(0)=(1/2)^3.

    So the probability of getting at least one success is the complement, or P(1,2,3)=1-(1/2)^3 = 7/8

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