Friday
March 24, 2017

Post a New Question

Posted by on Wednesday, February 29, 2012 at 9:01pm.

For H2(g) + Br2(g) -> 2HBr(g) k=64
<-

Ice table:
H2 Br2 HBr
I 0.10 0.10 0
C -x -x +2x
E

Solve for HBr at equilibrium

I do not know how to start this.

  • Chemistry - , Wednesday, February 29, 2012 at 9:06pm

    I tryed and got .20. Is this correct?

  • Chemistry - , Wednesday, February 29, 2012 at 9:18pm

    Where did the 1.0, 10.0 and 10.0 come from?

  • Chemistry - , Wednesday, February 29, 2012 at 9:30pm

    Those were the values that the teacher put in there. I just assumed that since H2 and Br2 are -x and HBr is +2x that HBr would be 2 X 0.10..

  • Chemistry - , Wednesday, February 29, 2012 at 9:36pm

    Did the teacher put them in as initial concentrations or are they changes or equilibrium concentrations?

  • Chemistry - , Wednesday, February 29, 2012 at 9:41pm

    He didn't say, he just posted the question like above.

  • Chemistry - , Wednesday, February 29, 2012 at 10:14pm

    What are you supposed to do with the numbers? What's the question?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question