A 50KG BLOCK IS BEING PULLED BY
a 200-N FORCE ON A HORZONTAL ROUGH SURFACE AS SHOWN IN DIAGRAM.IF THE COEFFICIENT OF KINETIC FRICTION BETWEEN THE BLOCK AND THE SURFACE IS 0.3. FIND THE ACCELERATION OF THE BLOCK
A 1500- KG CAR IS MOVING WITH A VELOCITY OF 20m/s on a straight road when the brakes are applied uniformly. The car stops after traveling a distance of 200m.what is the braking force on the car?
1/2xMxV^2=FxX X=distance
1/2x1500x20^2=Fx200
F=1500N
To find the acceleration of the block, we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
First, let's calculate the force of friction that is opposing the motion of the block. The force of friction can be calculated using the formula:
Force of Friction (Ff) = Coefficient of Friction (μ) * Normal Force (Fn)
In this case, the normal force (Fn) is equal to the weight of the block, which is mg. The formula for weight is:
Weight (W) = mass (m) * acceleration due to gravity (g)
Given that the mass of the block is 50 kg and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight:
Weight (W) = 50 kg * 9.8 m/s² = 490 N
Now we can calculate the force of friction:
Ff = 0.3 * 490 N = 147 N
Since the block is being pulled with a force of 200 N, we need to account for the force of friction opposing the motion. The net force (Fnet) acting on the block will be:
Fnet = 200 N - 147 N = 53 N
Finally, we can use Newton's second law to find the acceleration (a):
Fnet = ma
Solving for acceleration:
a = Fnet / m
a = 53 N / 50 kg
a ≈ 1.06 m/s²
Therefore, the acceleration of the block is approximately 1.06 m/s².