Calculus (Area Between Curves)
posted by Mishaka on .
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2) and y=44x.
You get:
a.)1.8467
b.) 0.16165
c.) 0.36974
d.) 1.7281
e.) 0.37859
Based on my calculations, I would say that the answer is e.) 0.37859. I am checking my answer.

That's the correct answer.
If you integrated between the endpoints 0, 0.69275, 0.92811, you should have got the areas 0.28024 and 0.09835 respectively, which add up to 0.37859. 
Thank you, I was just really unsure of my answer!

You're welcome! :)