Posted by Mishaka on Wednesday, February 29, 2012 at 4:21pm.
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2) and y=44x.
You get:
a.)1.8467
b.) 0.16165
c.) 0.36974
d.) 1.7281
e.) 0.37859
Based on my calculations, I would say that the answer is e.) 0.37859. I am checking my answer.

Calculus (Area Between Curves)  MathMate, Wednesday, February 29, 2012 at 4:44pm
That's the correct answer.
If you integrated between the endpoints 0, 0.69275, 0.92811, you should have got the areas 0.28024 and 0.09835 respectively, which add up to 0.37859.

Calculus (Area Between Curves)  Mishaka, Wednesday, February 29, 2012 at 4:47pm
Thank you, I was just really unsure of my answer!

Calculus (Area Between Curves)  MathMate, Wednesday, February 29, 2012 at 4:51pm
You're welcome! :)
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