Posted by **Mishaka** on Wednesday, February 29, 2012 at 4:21pm.

Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2) and y=4-4x.

You get:

a.)1.8467

b.) 0.16165

c.) 0.36974

d.) 1.7281

e.) 0.37859

Based on my calculations, I would say that the answer is e.) 0.37859. I am checking my answer.

- Calculus (Area Between Curves) -
**MathMate**, Wednesday, February 29, 2012 at 4:44pm
That's the correct answer.

If you integrated between the end-points 0, 0.69275, 0.92811, you should have got the areas 0.28024 and 0.09835 respectively, which add up to 0.37859.

- Calculus (Area Between Curves) -
**Mishaka**, Wednesday, February 29, 2012 at 4:47pm
Thank you, I was just really unsure of my answer!

- Calculus (Area Between Curves) -
**MathMate**, Wednesday, February 29, 2012 at 4:51pm
You're welcome! :)

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