Posted by **Mishaka** on Wednesday, February 29, 2012 at 3:44pm.

Find the area of the region bounded by the curves y=x^(-1/2), y=x^(-2), y=1 and y=3.

You get:

a.) 1/2(sqrt(3)) + 4/3

b.) 2(sqrt(3)) - 8/3

c.) 1/2(sqrt(3) - 32/3

d.) 2(sqrt(3)) - 32/3

e.) 8/3 - 2(sqrt(3))

- Calculus (Area Between Curves) -
**Nade**, Wednesday, February 29, 2012 at 4:09pm
The definite integral of y^-.5-y^-2 evaluated from 1 to 3. I forgot 2sqrt(3)-8/3 choice b

- Calculus (Area Between Curves) -
**Mishaka**, Wednesday, February 29, 2012 at 4:11pm
I got the same thing. Working out the other answers, they were either negative or obviously too large of an area for the given bounds, thank you Nade!

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