I need to find the volume of 5.44 molar nitric acid needed to completely react with 6.27 grams of Ca(OH)2.

Ca(OH)2 + 2HNO3 ==> 2H2O + Ca(NO3)2

mols Ca(OH)2 = grams/molar mass
moles HNO3 = twice that (from the balanced equation).
M HNO3 = mols HNO3/L HNO3. You know M and mols, solve for L and convert to mL.