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March 3, 2015

Posted by **Ashley** on Wednesday, February 29, 2012 at 1:00pm.

The acceleration of gravity is 9.8 m/s2. What is the centripetal acceleration of a rider?

Answer in units of m/s2

- Physics. PLEASE HELP!! -
**drwls**, Wednesday, February 29, 2012 at 1:22pmThe centripetal acceleration does not depend upon g or the position on the wheel (top, bottom side etc.)

It equals V^2/R

In this case,

V = pi*17m/15s = 3.56 m/s

R = 17/2 = 8.5 m

Now compute V^2/R for the answer.

- Physics. PLEASE HELP!! -
**Ashley**, Wednesday, February 29, 2012 at 1:27pmThank You!!!

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