Posted by **Helga** on Wednesday, February 29, 2012 at 8:41am.

The coefficient of x^2 in the expansion of (4-3x)^n as a series of ascending powers of x is -9/64. Show that n satisfies the equation 4^(n+1)=2/[n(1-n)] and hence verify that n=1/2.

I can do the first part of the problem:

4^n*3^2*n(n-1)/2!*2^4=-3^2/2^6

4*4^n*n(n-1)=-2

4^(n+1)*n(n-1)=-2

4^(n+1)=2/[n(1-n)]

But unfortunately I'm stuck with the verification of n=1/2.

Please help.

- Binomial expansion -
**MathMate**, Wednesday, February 29, 2012 at 10:04am
The binomial expansion is usually expressed as:

(p+q)^n

=∑ (n,r)p^i*q^(n-i)

for i=0,n

where (n,r)=n!/[r!(n-r)!]

so for

p=4

q=-3x

i=(n-2)

(n,r)=n*(n-1)/2!

[note: (n,r)=(n,n-r), so (n,n-2)=(n,2)]

so term n-2 is

[n(n-1)/2!]*[4^(n-2)]*[(-3x)^2]

=[n(n-1)/2!]*[4^(n-2)]*[9]x²

and the coefficient

[n(n-1)/2!]*[4^(n-2)]*[9] = -9/64

Solve for n by trying various values of n that gives -9/64 on the left-hand side.

I get n=1/2.

## Answer this Question

## Related Questions

- maths - in the binomial expansion of (1+x/k)^n, where k is a constant and n is a...
- binomial expansion - how do you expand the following as a series of ascending ...
- maths - find the first 3 terms in the expansion of (x+4)(1+3x)^-2 as a series in...
- same type of binomial theorem question - Question: Find the first 3 terms in the...
- algebra - Find 1.The first 4 terms of the binomial expansion in ascending powers...
- maths - Obtain the binomial expansion of (2-x) (1+1/2x)^8 in ascending powers of...
- maths - Use binomial theorem to to expand squareroot of 4+x in ascending powers ...
- algebra - Find 1. the binomial expansion of (3+2x)^5 simplifying terms. Hence ...
- Maths - Find the first four terms in the binomial expansion of (1+x)^(1/5) and ...
- Maths - Find the first four terms in the binomial expansion of (1+x)^(1/5) and ...

More Related Questions