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November 23, 2014

November 23, 2014

Posted by **Mallory** on Wednesday, February 29, 2012 at 8:04am.

- Math -
**MathMate**, Wednesday, February 29, 2012 at 9:14amIf it is in factored form, it should have a common factor for the whole expression.

(4x+5) is not a factor for the whole expression, just the first term (before the + sign).

To factor "completely", we need to expand the expression, collect similar terms and factor from there.

(4x + 5) (2x - 1) + (x - 9) (2x - 1)

=8x²+6x-5 + 2x²-19x+9

=10x²-13x+4

=(5x-4)(2x-1)

- Math -
**Steve**, Wednesday, February 29, 2012 at 10:57amOr, note that (2x-1) is a common factor, so if you factor it out, you get

(2x-1)(4x+5 + x-9) = (2x-1)(5x-4)

- Math -
**MathMate**, Wednesday, February 29, 2012 at 3:26pmThanks, Steve!

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