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March 1, 2015

March 1, 2015

Posted by **danny** on Tuesday, February 28, 2012 at 11:08pm.

i have trouble this problem. my math book is not really clear.

Find the slope of the tangent line to the curve √(3x+2y)+√(4xy)=11.6 at the point (6,2).

√(3x+2y) is the square root(3x+2y)

√(4xy)is the square root 4xy.

- Calculus: Implicit -
**bobpursley**, Tuesday, February 28, 2012 at 11:35pm1/2sqrt(3x+2y)* (3 +2yy')+ 1/2sqrt(4xy)*(4y+2xy')=0

now at the point 6,2, put that into the equation for x,y

and solve for y'

- Calculus: Implicit -
**danny**, Wednesday, February 29, 2012 at 11:40pm1/2 √(3(6)+2(2)) * 3(2(2))+ 1/2 √(4(6)(2)) * 4(2)+2(6) right?

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