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December 21, 2014

Posted by **liz** on Tuesday, February 28, 2012 at 9:51pm.

I got 47/66 that the balls are different colors...is that right?

- Math for the middle school and elementary teacher -
**MathMate**, Tuesday, February 28, 2012 at 9:59pmCorrect! Well-done!

P(RR)=(3/12)(2/11)=6/132

P(GG)=(4/12)(3/11)=12/132

P(YY)=(5/12)(4/11)=20/132

Probability to draw two of same colour

=(6+12+20)/132=19/66

=>

Probability to draw two of different colours

=(66-19)/66=47/66

- Math for the middle school and elementary teacher -
**bobpursley**, Tuesday, February 28, 2012 at 10:05pmhttp://www.futureaccountant.com/probability/problems-solutions/drawing-picking-selecting-two-three-more-balls-box-bag-urn-04.php and many variations of the same bag.

- Math for the middle school and elementary teacher -
**liz**, Tuesday, February 28, 2012 at 10:09pmThank you very much for you help:)

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