A cylindrical tin can has a radius of 4.5cm and a height of 5 cm

(a)What is the surface area of the can

(b)What is its volume?

(c)What is the cans capacity

Total surface area (includes lateral and both ends)

=2πr(r+h)
=2π(4.5+5)
=19π cm²

Volume = πr²h cm³

Capacity = πr²h ml

could somebody help me and write this out from a-c i need the answers so i can pass my math course

50=2x

Im having difficulties with this one also...

To calculate the surface area of the cylindrical tin can, you need to find the area of the two circular bases and the lateral surface area.

(a) Surface Area of the Can:
The formula to find the surface area of a cylinder is:
Surface Area = 2πrh + 2πr²

Given:
Radius (r) = 4.5 cm
Height (h) = 5 cm

Substituting the values into the formula:
Surface Area = 2π(4.5 cm)(5 cm) + 2π(4.5 cm)²
Surface Area = 2π(22.5 cm²) + 2π(20.25 cm²)
Surface Area ≈ 142.2 cm² + 127.8 cm²
Surface Area ≈ 270 cm²

Therefore, the surface area of the cylindrical tin can is approximately 270 cm².

(b) Volume of the Can:
The formula to find the volume of a cylinder is:
Volume = πr²h

Given:
Radius (r) = 4.5 cm
Height (h) = 5 cm

Substituting the values into the formula:
Volume = π(4.5 cm)²(5 cm)
Volume = π(20.25 cm²)(5 cm)
Volume ≈ 316.8 cm³

Therefore, the volume of the cylindrical tin can is approximately 316.8 cm³.

(c) Capacity of the Can:
The capacity of a cylindrical tin can refers to its internal volume, which we already calculated in part (b). Thus, the capacity of the can is approximately 316.8 cm³.