Post a New Question


posted by on .

A 7 kilogram bowling ball is dropped from a fourth story window. If each story is 3 meters high, use energy conservation (not the equations of motion) to find the ball's velocity when it strikes the ground. Ignore air resistance.

1/2 m v^2= mgh
v= sqrt (2g*(3+.5))

v=7.67 m/s

did I do this right? thanks

  • PHYSICS - ,

    The approach is correct...and the answer is correct for a one storey building.

    Replace (3+0.5) by (3*3+1)
    3 storeys+1m above floor.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question