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October 20, 2014

October 20, 2014

Posted by **Karen** on Tuesday, February 28, 2012 at 8:47pm.

- math -
**MathMate**, Tuesday, February 28, 2012 at 9:44pmProbability of individual rolls:

1. Prime: 2,3 or 5 out of 6 faces => P(prime)=3/6=1/2

2. "2" out of 6 faces, P(2) = ?

3. "5" out of 6 faces. P(5) = ?

We can reasonably assume that the three rolls are independent of each other. The required probability is therefore the product of the probability of the individual rolls.

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