how to find a pH for 0.10 M HCL?
please explain
All you need to do is to substitute into the pH equation.
pH = -log(H^+). HCl is a strong acid, it ionizes 100%; therefore, (HCl) = (H^+)
please explain
pH = -log(H^+). HCl is a strong acid, it ionizes 100%; therefore, (HCl) = (H^+)