Write balanced equations that describe the following reactions. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)
a) the dissociation of perchloric acid in water
b) the dissociation of propanoic acid (CH3CH2CO2H) in water
c) the dissociation of ammonium ion in water
a) The balanced equation for the dissociation of perchloric acid (HClO4) in water (H2O) can be written as:
HClO4 (aq) → H+ (aq) + ClO4- (aq)
b) The balanced equation for the dissociation of propanoic acid (CH3CH2CO2H) in water (H2O) can be written as:
CH3CH2CO2H (aq) → H+ (aq) + CH3CH2CO2- (aq)
c) The dissociation of the ammonium ion (NH4+) in water (H2O) can be written as:
NH4+ (aq) → H+ (aq) + NH3 (aq)
a) The balanced equation for the dissociation of perchloric acid (HClO4) in water can be written as:
HClO4(aq) -> H+(aq) + ClO4-(aq)
In this reaction, perchloric acid (HClO4) dissociates into hydrogen ions (H+) and perchlorate ions (ClO4-) in water.
b) The balanced equation for the dissociation of propanoic acid (CH3CH2CO2H) in water can be written as:
CH3CH2CO2H(aq) -> H+(aq) + CH3CH2CO2-(aq)
In this reaction, propanoic acid (CH3CH2CO2H) dissociates into hydrogen ions (H+) and propanoate ions (CH3CH2CO2-) in water.
c) The dissociation of ammonium ion (NH4+) in water can be represented as:
NH4+(aq) -> H+(aq) + NH3(aq)
In this reaction, the ammonium ion (NH4+) dissociates into a hydrogen ion (H+) and ammonia (NH3) in water.
One to get you started.
HClO4(l) + H2O(l) ==> H3O^+(aq) + ClO4^-(aq)