Thursday

November 27, 2014

November 27, 2014

Posted by **Ann** on Tuesday, February 28, 2012 at 6:49pm.

6(1.02^3x + 1) = 11

How do i find the answer after

1.03^3x +1 = (11/6)

Do i put a log on 1.03 or do I do something else

Thank you.

- Pre-Cal Help Please!! -
**Damon**, Tuesday, February 28, 2012 at 7:00pm1.03^3x +1 = (11/6)

the way you typed it:

1.03^3x = 11/6 - 6/6 = 5/6

3x (log 1.03) = log 5 - log 6

3 x = 48.72

x = 16.24

if you meant to type

1.03^(3x +1) = (11/6)

then

(3x+1)log1.03 = log 11 - log 6

3x+1 = 78.64

x = 25.9

**Answer this Question**

**Related Questions**

Cal 1 - Use Newton's method with the specified initial approximation x1 to find ...

Algebra II - Please check the following: Solve log4(m-3)+ log4(m+3) =2 Answer: 1...

math - round result to two decimal places...the answer i have is: 7.023 so two ...

college algebra - Solve the exponential equation using logarithms. Give the ...

college algebra - Solve the exponential equation using logarithms. Give the ...

Calc - I am having trouble with these two problems for my Calc class. I have ...

Calculus - Consider the function below. f(x) = [1-(4/x)]^x (a) Use a graph to ...

math - Suppose that x is normally distributed with a mean of 10 and a standard ...

pre-cal - Find the solution of the exponential equation, correct to four decimal...

pre-cal - Find the solution of the exponential equation, correct to four decimal...