Posted by Unknown on Tuesday, February 28, 2012 at 4:28pm.
pH = pKa + log(base)/(acid)
4.60 = 4.74+ log b/a
b/a = about 0.7 but that's approximate and you need to do it better than that.
You want the buffer to be 0.3M in acetate which means
a + b = 0.3
Solve the two equations simultaneously to obtain a and b. I obtained about 0.2M for (a) and about 0.1M for (b).
Since you want only 500 mL of the buffer, divide those numbers by 2 to obtain mol.
For #1, mols b x molar mass NaC2H3O2 = grams sodium acetate.
for #2, M = moles HCl/L HCl. You know moles and M, solve for L and convert to mL.
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