Sunday

December 21, 2014

December 21, 2014

Posted by **Bryant** on Tuesday, February 28, 2012 at 12:51pm.

(x,y)->(1,0)

alright i approached this at y=0. and got the limit as 3. where else can i approach this from to see if the limit really exist which im hoping it doesn't. i tried y=x-1 and that was a mess and i also tried y=mx which did nothing.

- Calculus -
**Steve**, Tuesday, February 28, 2012 at 1:22pmHmmm. . . Looks like a removable singularity to me.

x^3 - 1 = (x-1)(x^2 + xy + y^2)

x^3+2x^2y+xy^2-x^2-2xy-y^2

= x(x+y)^2 - (x+y)^2

= (x-1)(x+y)^2

so, f(x,y) = (x^2+xy+y^2)/(x+y)^2 for x≠1

limit as (x,y) -> (1,0) = (1)/(1)^2 = 1

**Answer this Question**

**Related Questions**

Calculus. Limits. Check my answers, please! :) - 4. lim (tanx)= x->pi/3 -(...

calculus - lim (x^3-1)/(x^3+2x^2y+xy^2-x^2-2xy-y^2) (x,y)->(1,0) my question ...

calculus help please - hi what is lim as x reaches one of the function x/LN(x) ...

Calculus, please check my answers! - 1. Evaluate: lim x->infinity(x^4-7x+9)/(...

calculus - 1)A function g is defined for all real numbers and has the following ...

calculus - Find lim (with x under it) (x^2-1)/x or state that the limit does...

Calculus help, please! - 1. Evaluate: lim x->infinity(x^4-7x+9)/(4+5x+x^3) 0...

Calculus 3 - Find the limit, if it exists, or show that the limit does not ...

Calculus 3 - Find the limit, if it exists, or show that the limit does not exist...

mathematics - Show that the limit does not exist for the function Lim (x,y)&#...