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September 2, 2014

September 2, 2014

Posted by **Cait** on Monday, February 27, 2012 at 11:35pm.

- DUE AT MIDNIGHT PLEASE HELP- Calculus -
**Steve**, Monday, February 27, 2012 at 11:56pmwork = force * distance

force = gm

consider thin sheets of water of area 5*(y/4) where y/4 is the width across the tank at depth y

So, the weight of the sheet of volume dV is 1000kg/m^3 * 9.8N/kg * 5(y/4)dy m^3 = 12250y * dy N

Work = Int[0,4] 12250y dy

= 6125 y^2 [0,4]

= 98000N

Check my math. . .

- Calculus - PS -
**Steve**, Monday, February 27, 2012 at 11:58pmMy bad. The water sheet at height y needs to be lifted (4-y)m. Make the fix and recalculate it.

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