Chemistry(Please help, thank you)
posted by Hannah on .
I have to calculate the concentration of I2 produced (# of moles of I2 produced / L) based on the stoichiometric ratio in the following equation.
2S2O3^2- + I2 -> 2I^- + S4O6^2-
Chemistry(Urgent, please help) - DrBob222, Sunday, February 26, 2012 at 9:47pm
If you know the number of moles of S2O3^2- then the number of mols I2 will be 1/2 that. I suspect you have M and L of S2O3^- and M x L = moles S2O3^2-.
Chemistry(Urgent, please help) - DrBob222, Monday, February 27, 2012 at 12:47am
moles = M x L
M is the concentration correct?
Yes m is
Is L just the unit? Moles would be 3.33e-3M / L ?
Yes u remember where it says mxL this means that your multiplying m by l and l would be the unit
So to find the amount of I2 produced as I first posted, it would be 1/2 that of 3.33e-3 correct? So 0.0666? Sorry, its important that I understand this correct
Yes i tried your question and this is what i received
So the answer would be 6.66e-2 L*min? Is that the correct unit?
Sorry I actually got 0.00666 so it would be 6.6e-3 correct?
So I got 6.6e-3 L*min for the amount of I2 produced. Now I have to calculate the rate for each of the 5 flasks used, so is the answer going to be the same for all 5?? It says to calculate the rate of reaction for each run using # of moles of I2 produced/L*min as the unit.