if the average of 80, 95, 100, 75 and n is 85, what is n?
Average = mean = Σx/n
X= value of scores and n = number of scores.
I am assuming that here you are using n merely as another score.
85 = (80+95+100+75+n)/6
Solve for n.
85 = (80+95+100+75+n)/5
To find the value of "n," we can use the concept of an average. The average of a set of numbers is the sum of all the numbers divided by the total count of numbers in the set.
In this case, we are given the average as 85 and four out of the five values. Let's calculate the sum of these four numbers:
Sum = 80 + 95 + 100 + 75
Sum = 350
Now, we know that the average is equal to the sum of all the numbers divided by their count. Since the average is 85 and we have four numbers, we can set up the following equation:
85 = Sum / 5
Substituting the value of the sum, we have:
85 = 350 / 5
Now, we need to solve for "n." Rearranging the equation, we get:
350 = 85 x 5
Dividing both sides by 5, we find:
70 = 85
However, this equation is not true. It means that our initial assumption was incorrect, and there is no value of "n" that satisfies the given conditions.
Therefore, there is no solution for "n" in this case.