physics
posted by Candy on .
A skier slides horizontally along the snow for a distance of 22.3 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.0500. Initially, how fast was the skier going?

KE2  KE1= A(friction).
KE2  KE1=0(m•v^2)/2=  (m•v^2)/2.
A(friction) = F(friction)•s•cosα = k•m•g•s•(1) =  k•m•g•s.
(m•v^2)/2= k•m•g•s.
v=sqroot (2•k•g•s)=
=sqroot (2•0.05•9.8•22.3)=21.85 m/s.