Calculus
posted by Anonymous on .
Let f be the function defined by f(x)= x^3 + ax^2 +bx + c and having the following properties.
1. the graph of f has a point of inflection at (0,2).
2. The average value of f(x) on the closed interval (0,2) is 3.
Determine the values of a,b and c

f' = 3x^2 + 2ax + b
f'' = 6x + 2a
f''(0) = 2, so
6*0 + 2a = 2
a = 1
f = x^3  x^2 + bx + c
Hey! (0,2) is
a) not a closed interval
b) not written as [low,hi]
Watch this space for further correct info. 
also, my value for a is bad. I'll fix it when the rest of the correction arrives.