Posted by **Anonymous** on Monday, February 27, 2012 at 2:46pm.

Let f be the function defined by f(x)= x^3 + ax^2 +bx + c and having the following properties.

1. the graph of f has a point of inflection at (0,-2).

2. The average value of f(x) on the closed interval (0,-2) is -3.

Determine the values of a,b and c

- Calculus - Incomplete -
**Steve**, Monday, February 27, 2012 at 4:02pm
f' = 3x^2 + 2ax + b

f'' = 6x + 2a

f''(0) = -2, so

6*0 + 2a = -2

a = -1

f = x^3 - x^2 + bx + c

Hey! (0,-2) is

a) not a closed interval

b) not written as [low,hi]

Watch this space for further correct info.

- Calculus - PS -
**Steve**, Monday, February 27, 2012 at 4:03pm
also, my value for a is bad. I'll fix it when the rest of the correction arrives.

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