Posted by **Help Please** on Monday, February 27, 2012 at 5:54am.

Would someone please be kind enough to explain steps for this one. Thank you.

If m and n are positive integers and m is 250% of n, what percent of m is 2n?

- Math Help Please -
**Reiny**, Monday, February 27, 2012 at 8:29am
m = 2.5n

2m = 5n

n = (2/5)m

2n = (4/5)m

4/5 = .8 = 80%

e.g.

let n = 10, then m = 25

then 2n = 20

percentage of 25 is 20 --> 20/25 = .8 = 80%

- Math Help Please -
**thanker**, Monday, May 14, 2012 at 4:58pm
thank you reiny i really needed it thank you soo much!!

## Answer this Question

## Related Questions

- Math SOmeone please please help - Find the derivative of the function. g(u) = (5...
- math help please - Let f:ℤ+ → ℤ+ be the function defined by: ...
- MATH - How many positive integers in the set {50, 51,, . . . , 298, 299} do not ...
- Math - Provide an example of at leave five ordered pairs that do not model a ...
- math - I asked this question but no one answered it. Can someone please help ...
- Planning (URGENT) - Describe 5 positive activities, events, or experiences in ...
- Algebra--please help! - This one, I am very confused on and I have no idea how ...
- math - is the set of positive integers the same as the set of nonegative ...
- algebra!!!! please help me!!!! - The smallest possible positive value of 1−...
- Math - Two positive integers are in ratio 1:3. If their sum is added to their ...

More Related Questions