Posted by shabna on Monday, February 27, 2012 at 3:55am.
An arithmetic progression (A.P) or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
If the initial term of an arithmetic progression is a1 and the common difference of successive members is d, then the nth term of the sequence is given by:
a n = a 1 + ( n - 1 ) d
a 1 = first term
In this case:
a 8 = a 1 + ( 8 - 1 ) d
a 8 = a 1 + 7 d = 18
a 15 = a 1 + ( 15 - 1 ) d
a 15 = a 1 + 14 d
a 9 = a 1 + ( 9 - 1 ) d
a 9 = a 1 + 8 d
a 15 - a 9 = ( a 1 + 14 d ) - ( a 1 + 8 d )
a 15 - a 9 = a 1 + 14 d - a 1 - 8 d
a 15 = a 1 - a1 + 14 d - 8 d
a 15 - a 9 = 6 d
a 15 - a 9 = 30
6 d = 30 Divide both sides by 6
d = 30 / 6
d = 5
a 8 = a 1 + 7 d = 18
a 1 + 7 * 5 = 18
a 1 + 35 = 18
a 1 = 18 - 35
a 1 = - 17
A.P
a n = - 17 + ( n - 1 ) * 5
- 17 , - 12 , - 7 , - 2 , 3 , 8 , 13 , 18 , 23 , 28 , 33 , 38 , 43 , 48 , 53
It is given that 4th term is 18 a4=18 a+3d=18
a=18-3d -(1)
a15-a9=a+14d-1-8d=30
6d=30
d=5
a=18-15=3
A.P is
3,8,13,18,23.....