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March 1, 2015

March 1, 2015

Posted by **muzungu** on Monday, February 27, 2012 at 2:43am.

- maths -
**L.Bianchessi**, Monday, February 27, 2012 at 2:55amWell you subtract the 16 to get your equation equal to one.

Do x^2/16 + y^2/4=1

Your center is 0,0

Your eclipse would be horizontal.

Do when graphing put a point at (0,0) then go 4 spaces in the negative and positive direction on the x-axis. Then go up 2 spaces from (0,0) in the positive and negative directions on the y-axis. Put your points on the graph. Draw your ellipse.

Then you know to find your c, you do c^2=a^2 -b^2. So that's c^2= 16-4. Which makes c=2radical3

Eccentricity= c/a

So 2radical3/ 4.......e= radical 3 / 2

Foci= (+/- 2radical3, 0)

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