Posted by omar on Monday, February 27, 2012 at 1:57am.
Find the roots of the given equation by completing the square.
αx^2 + βx + δ = 0

Algebra  L.Bianchessi, Monday, February 27, 2012 at 2:23am
Do you mean ax^2+ bx+c=0 ??

Algebra  Steve, Monday, February 27, 2012 at 12:59pm
I think that's safe. The symbols used don't really matter. It's easier to type Roman letters, so I'll use those
ax^2 + bx + c = 0
a(x^2 + b/a x) = c
a(x^2 + b/a x + (b/2a)^2) = (b/2a)^2  c
a(x + (b/2a))^2 = (b^2  4ac)/4a
(x + b/2a)^2 = (b^2  4ac)/4a^2
x + b/2a = ±√(b^2  4ac)/2a
x = [b ± √(b^2  4ac)]/2a
Look familiar?

Algebra  Henry, Wednesday, February 29, 2012 at 10:21am
post it.
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