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Algebra

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Find the roots of the given equation by completing the square.

αx^2 + βx + δ = 0

  • Algebra - ,

    Do you mean ax^2+ bx+c=0 ??

  • Algebra - ,

    I think that's safe. The symbols used don't really matter. It's easier to type Roman letters, so I'll use those

    ax^2 + bx + c = 0
    a(x^2 + b/a x) = -c
    a(x^2 + b/a x + (b/2a)^2) = (b/2a)^2 - c
    a(x + (b/2a))^2 = (b^2 - 4ac)/4a
    (x + b/2a)^2 = (b^2 - 4ac)/4a^2
    x + b/2a = ±√(b^2 - 4ac)/2a

    x = [-b ± √(b^2 - 4ac)]/2a

    Look familiar?

  • Algebra - ,

    post it.

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