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January 30, 2015

Posted by **omar** on Monday, February 27, 2012 at 1:57am.

αx^2 + βx + δ = 0

- Algebra -
**L.Bianchessi**, Monday, February 27, 2012 at 2:23amDo you mean ax^2+ bx+c=0 ??

- Algebra -
**Steve**, Monday, February 27, 2012 at 12:59pmI think that's safe. The symbols used don't really matter. It's easier to type Roman letters, so I'll use those

ax^2 + bx + c = 0

a(x^2 + b/a x) = -c

a(x^2 + b/a x + (b/2a)^2) = (b/2a)^2 - c

a(x + (b/2a))^2 = (b^2 - 4ac)/4a

(x + b/2a)^2 = (b^2 - 4ac)/4a^2

x + b/2a = ±√(b^2 - 4ac)/2a

x = [-b ± √(b^2 - 4ac)]/2a

Look familiar?

- Algebra -
**Henry**, Wednesday, February 29, 2012 at 10:21ampost it.

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