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April 23, 2014

April 23, 2014

Posted by **Lucy** on Monday, February 27, 2012 at 12:58am.

a)find the unit vector in direction of p.

b) find the directional derivative at p in the direction of <0,-1/(sqrt2),-1/(sqrt2)>

- cal3 -
**Steve**, Monday, February 27, 2012 at 12:52pm|

**p**| = √(4+1+1) = √6**u**=**p**/|**p**| = (2/√6,-1/√6,1/√6)

Now, with**u**= <0,-1/√2,-1/√2)>

∇<sub<**u**f = ∇f•**u**

= (y+z)(0) + (x+z)(-1/√2) + (x+y)(-1/√2)

= (0)(0) - 1/√2 (2+1) - 1/√2 (2-1)

= -4/√2 = -2√2

- cal3 -
**Lucy**, Monday, February 27, 2012 at 7:07pmOh crap typo error, should read find the unit vector in direction of maximum increase of f in the direction of P.

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