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July 29, 2014

July 29, 2014

Posted by **Lucy** on Monday, February 27, 2012 at 12:53am.

z= x^2 + y^2, x=sin(2t), y=cos(t)

- cal3 -
**Steve**, Monday, February 27, 2012 at 12:10pmz = x^2 + y^2

dz/dt = 2x dx/dt + 2y dy/dt

= 2sin(2t) * 2cos(2t) + 2cos(t) * (-sin(t))

= 4cos(4t) - sin(2t)

for dz/dt=0, check wolframalpha and enter

**solve 4cos(4t) - sin(2t) = 0**

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