Posted by LISA on Monday, February 27, 2012 at 12:16am.
F(x)=f(x^4)
Using the chain rule,
F'(x)=f'(x^4)*(d(x^4)/dx)=f'(x^4)*3x^3
substitute x for a and all the numerical values supplied to find F'(a).
Similarly, G(x)=(f(x))^4
Apply the chain rule successively,
G'(x)=(d/dx)(f(x))^4)
=4f(x)^3*f'(x)
So G'(a)=4f(a)^3*f'(a)
Although f'(a) is known, it is not clear to me how we can find f(a).
Related Questions
College Math II - Solve each problem. Find the quotient and remainder when x^2...
Math - Let f(x) = 1/(x+7)+15/(x-8). Find all a for which f(a)=f(a+15). How do I ...
statistics - I need to find the class midpoint, boundaries and class with for ...
College Math II - Solve the problem. If a manufacturer charges q dollars each ...
Math - 3x-4 to y+15 is constant and y=3 when x=2 then when y=12, x equals? My ...
Math problem still stuck - Let f(x) = 1/(x+7)+15/(x-8). Find all a for which f(a...
Calculus: for mathmate - Find the slope of the tangent line to the graph of the ...
Math - I am in Calculus and am currently learning how to find the Area of a ...
math--pre alg - not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12...
College Math II - Write a complete solution to each problem. If the length of a ...
For Further Reading
