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A 7 kilogram bowling ball is dropped from a fourth story window. If each story is 3 meters high, use energy conservation (not the equations of motion) to find the ball's velocity when it strikes the ground. Ignore air resistance.


    1/2 m v^2= mgh
    v= sqrt (2g*(3+.5))

    I am assuming the window on the 4th floor is halfway up.

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