posted by brad .
A mixture formed by adding 55.0 mL of a 1.5x10^-2 M HCl to 140 mL of 1.0x10^-2 M HI.
How do you calculate the pH for this problem?
Both HCl and HI are strong acids; therefore add them.
mols HCl = M x L = ?
mols HI = M x L = ?
mols (H^+) = ? + ?
Then M = moles/total volume in liters.