Posted by Taeyeon on Sunday, February 26, 2012 at 4:06pm.
3x^2+2xy+y2=2
6x + 2y + 2xy' + 2yy' = 0
x=1 ==> y=-1
6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0
6 - 2 + 2y' - 2y' = 0
4 = 0
(e) undefined
The graph is an ellipse. At (1,-1) there is a vertical tangent
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