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December 18, 2014

December 18, 2014

Posted by **Taeyeon** on Sunday, February 26, 2012 at 4:06pm.

A. -2 B. 0 C. 2 D. 4 E. not defined

- calculus -
**Steve**, Monday, February 27, 2012 at 12:33am3x^2+2xy+y2=2

6x + 2y + 2xy' + 2yy' = 0

x=1 ==> y=-1

6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0

6 - 2 + 2y' - 2y' = 0

4 = 0

(e) undefined

The graph is an ellipse. At (1,-1) there is a vertical tangent

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