The 20kg object is dropped from a height of 2 meters. Find its speed when it hits the ground. Give your answer in meters per second.
There's an easy formula to figure out how fast something will be at the end of a fall.
Square root of (2gh).
Mass isn't even involved
Sq.Rt.(2 x 9.8 x 2)
Sq.Rt.(39.2)
6.26 m/s
Speed =d×t. =55×10=550
To find the speed of the object when it hits the ground, we can use the principles of motion and apply the equations of motion.
The equation we can use is:
v^2 = u^2 + 2as
Where:
v = final velocity (the speed when the object hits the ground)
u = initial velocity (which is 0 in this case because the object is dropped)
a = acceleration due to gravity (approximately 9.8 m/s^2)
s = distance (which is the height of 2 meters)
Plugging in the values into this equation, we get:
v^2 = 0^2 + 2 * 9.8 * 2
Simplifying further:
v^2 = 0 + 2 * 9.8 * 2
v^2 = 39.2
To find v, we need to square root both sides:
v = √39.2
Calculating the square root of 39.2, we get:
v ≈ 6.26 m/s
Therefore, the speed of the 20kg object when it hits the ground is approximately 6.26 meters per second.