Cocaine is a non-electrolyte that has a molecular weight of 303.4 g/mole. How many grams must be dissolved in 25.0 mL of Chloroform (density = 1.484 g/mL) to raise its boiling point to 65.5 Celsius? The boiling point of pure Chloroform is 61.2 Celsius.

Kb Chloroform = 3.62 Celsius/m

Again I know to solve for m. But then I don't know how to find the boiling point of pure Chloroform or what steps to even take next/what numbers to plug in.

Why do you have a problem with the boiling point of pure CHCl3? The problem gives that to you as 61.2 C.

Determine delta T, then
delta T = Kb*m
Solve for m

m cocaine= moles cocaine/kg solvent
You now know m cocaine, you know kg solvent, solve for moles cocaine.

moles cocaine = grams cocaine/molar mass cocaine.
Solve for grams.

To find the amount of cocaine that needs to be dissolved in chloroform, we need to use the formula for boiling point elevation:

ΔTb = Kb * m

Where:
ΔTb is the change in boiling point
Kb is the molal boiling point constant of the solvent
m is the molality of the solute

In this case, the change in boiling point (ΔTb) is given as 65.5°C - 61.2°C = 4.3°C. The molal boiling point constant (Kb) for chloroform is given as 3.62 °C/m.

To find the molality (m) of the solute, we need to use the formula:

m = (moles of solute) / (mass of solvent in kg)

To find the boiling point of pure chloroform, we need to calculate the molality (m) first using the formula above.

Given that the density of chloroform is 1.484 g/mL and we have 25.0 mL, we can calculate the mass of the solvent:

Mass of solvent = volume × density
Mass of solvent = 25.0 mL × 1.484 g/mL = 37.1 g

We convert the mass of solvent to kg:

Mass of solvent = 37.1 g × (1 kg / 1000 g) = 0.0371 kg

Now we can calculate the molality (m):

m = (moles of solute) / (0.0371 kg)

To find the moles of solute, we can use the formula:

moles of solute = mass of solute / molar mass

The molar mass of cocaine is given as 303.4 g/mol. We are solving for the mass of solute.

Let's denote the mass of solute as "x" grams.

moles of solute = x / 303.4 g/mol

Substituting these values into the expression for molality:

m = (x / 303.4 g/mol) / 0.0371 kg

Now, we can rearrange the equation to solve for the mass of solute (x):

x = m × 303.4 g/mol × 0.0371 kg

Substitute the given values: m = 4.3 °C / (3.62 °C/m), which gives:

x = (4.3 °C / 3.62 °C/m) × 303.4 g/mol × 0.0371 kg

Simplifying further, we can find the value of x in grams.