Posted by **Jat** on Sunday, February 26, 2012 at 5:41am.

A particle is travelling with velocity (4i+5j)m/s. It undergoes an acceleration of magnitude 2.5m/s^2 in a direction given by the vector (3i-4j). Find the velocity and displacement of the particle from its initial position after 4s.

- Please help me with M1 kinematics! -
**Jat**, Sunday, February 26, 2012 at 10:34pm
In the direction of x

u = 4i, a= 2.5(3/5)

At t =4

v = u+at

v= 4 + 2.5 (3/5)4=4+6=10

In the direction of y

u = 5j, a= 2.5(-4/5)

At t =4

v = u+at

v= 5 + 2.5 (-4/5)4=5-8=-3

Hence

V = 10i-3j

Now we have initial and final velocities

r = 1/2(u +v)t

r = 1/2(4i+5j+10i-3j)4

r = 2(14i+2j)

r = 18i+4j

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