Posted by Jat on Sunday, February 26, 2012 at 5:41am.
A particle is travelling with velocity (4i+5j)m/s. It undergoes an acceleration of magnitude 2.5m/s^2 in a direction given by the vector (3i4j). Find the velocity and displacement of the particle from its initial position after 4s.

Please help me with M1 kinematics!  Jat, Sunday, February 26, 2012 at 10:34pm
In the direction of x
u = 4i, a= 2.5(3/5)
At t =4
v = u+at
v= 4 + 2.5 (3/5)4=4+6=10
In the direction of y
u = 5j, a= 2.5(4/5)
At t =4
v = u+at
v= 5 + 2.5 (4/5)4=58=3
Hence
V = 10i3j
Now we have initial and final velocities
r = 1/2(u +v)t
r = 1/2(4i+5j+10i3j)4
r = 2(14i+2j)
r = 18i+4j
Answer This Question
Related Questions
 Physics  A particle moves in the xy plane with constant acceleration. At time ...
 Physics  Uugghhh help please. The velocity of a 4.6 kg particle is given by ...
 calculus  5. A particle moves along the y – axis with velocity given by v(t)=...
 Maths mst  Question – 3: Consider a particle moving according to the velocity ...
 physics  The acceleration of a particle moving only on a horizontal plane is ...
 physics  The acceleration of a particle moving only on a horizontal plane is ...
 physics  The position vector r of a particle moving in the xy plane is r=2ti+...
 Physics  The acceleration of a particle moving only on a horizontal xy plane is...
 physics  A particle leaves the origin with an initial velocity = (2.35 m/s) and...
 Physics  A particle initially located at the origin has an acceleration of a= 5...
More Related Questions