Posted by cynthia on Sunday, February 26, 2012 at 1:43am.
1.
1 turns to 0
2x turns to 2
x^3 turns to 3x^2 (bring 3 up front & subtract 1 from exponent)
^1/4 goes up front and subtract 1 from that =-3/4
Final answer would be
1/4(3x^2+2)^-3/4
2. Use same procedure
1/3 (sec^2t) ^ -2/3
d/dx (u^n) = n u^(n-1) du/dx
Not quite Will.
I get
(1/4)(x^3+2x+2)^-3/4 [3x^2+2]
f(t)= (1+tant)^1/3
f'(t) = (1/3)(1+tan t)^-(2/3) [ sec^2 t]
Damon is right, I forgot to apply the chain rule.
Related Questions
college Calculus Help! - Find the derivative of the function. 1. F(x)= (1+2x+x^3...
college Calculus Help! - Find the derivative of the function. 1. F(x)= (1+2x+x^3...
calculus - Please find the Derivative of the function y =sec^2x + tan^2x
college calculus - find a and b so that f(x)=x^2+ax+b has a local min at (6,-5) ...
Calculus - Use the Product Rule to find the derivative of the function. f(x) = (...
calculus - You are given the following function. f(x)= (8+x)/(1-8x) (a) Find the...
calculus - At the indicated point for the function, find the following. A ...
calculus - Find the derivative of the function using the definition of ...
Calculus - Find the Derivative of the function: f(x)= ln(x^2/2x-3)
Calculus - Find the intervals of increase and decrease for the following ...
For Further Reading
