Posted by Rob on .
A box which has a mass of 14kg is sliding along a horizontal surface with a velocity of 18m/s when it encounters a frictionless inclined plane which meets the horizontal at an angle of 28 degrees. The box slides up the incline until it comes to a halt.
How far up the incline will the box slide before it stops? (35.2m)
its initial KE= final PE
1/2 m v^2= mgh=mg*distance*sin28
solve for distance.