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Balance each of the following redox equations using the half-reaction method.

HI(s) + H2SO4 (aq) --> H2S(g) + I2 (s)

My only question about this equation do I know how many electrons I need to put on both sides? Other than that I know how to do it.

  • chemistry - ,

    I in HI has an oxidation state of -1. On the other side I2 is zero. So in going from 2I^- to I2, I lost 2electrons.
    S in H2SO4 is +6. S in H2S is -2. In going from +6 to -2, there is a gain of 8 electrons. I do this intuitively but you can do it mathematically.
    +6-(-2) = +8 so gain of 8.
    -2-(0) = -2 so loss of 2.

  • chemistry - ,

    You carefully measure 20.00 of powder and add it to 81.00 of solution in a reaction flask of known mass. You notice bubbles as a reaction takes place. You then determine that the contents of the flask have a mass of 92.80 . The relevant equation is

    Assuming no other reactions take place, what mass of was produced in this reaction?
    Express the mass numerically in

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