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April 24, 2014

April 24, 2014

Posted by **Hannah** on Saturday, February 25, 2012 at 5:18pm.

- Physics -
**Elena**, Saturday, February 25, 2012 at 5:39pm27 feet = 8.23 m

PE =KE,

mgH = mv^2/2

v=sqroot(2gH)= 12.7 m/s.

If the collision with the ground is elastic, the height of the ball would be equal to its initial height. It cant reach the heigth of 15 m.

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