Posted by Hannah on Saturday, February 25, 2012 at 5:18pm.
27 feet = 8.23 m
PE =KE,
mgH = mv^2/2
v=sqroot(2gH)= 12.7 m/s.
If the collision with the ground is elastic, the height of the ball would be equal to its initial height. It cant reach the heigth of 15 m.
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