Homework Help: Physics

Posted by Allie on Saturday, February 25, 2012 at 1:16pm.

a 25 kg box is released from rest on a rough inclined plane tilted at an angle of 33.5 degrees to the horizontal. The coefficient of kinetic friction between the box and the inclined plane is 0.200.

a. determine the force of kinetic friction acting on the box
b. determine the acceleration of the box as it slides down the inclined plane.

Physics - Damon, Saturday, February 25, 2012 at 1:31pm
Normal force = m g cos 33.5
friction force = .2 m g cos 33.5

weight force component down slope = m g sin 33.5

total force down slope= mg(sin33.5-.2cos33.5)

a = F/m =g(sin33.5-.2cos33.5)
Physics - Anonymous, Saturday, February 25, 2012 at 3:44pm
H2(g)+N2(g)NH3(g) Please help balance this equation. Thank you

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