a body of mass 5 kg is thrown vertically upwards with a speed of 10m/s what is its k.e. when it is thrown find its potential energy when it reaches at highest poiint also find maximum height attained by the body?

a. KE = 0.5m*Vo = 2.5*(10)^2 = 250 Joules

b. hmax = (Vf^2-Vo^2)/2g.
hmax = (0-(10)^2 / -19.6 = 5.10 m.

c. PE = mg*h = 5 * 9.8 * 5.1=250 Joules

m=5kg

V=10m/s
K.E=1/2mv^2
P.E=mgh
K.E=P.E
K.E=1/2mv^2
=1/2x10x5x5
=125
P.E=125
Mgh =P.E
5x10xh=125
10h=125/5=25
h=25/10=2.5 answer

To find the kinetic energy (KE) of the body when it is thrown vertically upwards, we can use the formula for kinetic energy:

KE = 1/2 * m * v^2

where:
m = mass of the body (5 kg)
v = speed of the body (10 m/s)

Substituting the given values into the formula:

KE = 1/2 * 5 kg * (10 m/s)^2
= 1/2 * 5 kg * 100 m^2/s^2
= 1/2 * 500 kg * m^2/s^2
= 250 kg * m^2/s^2

Therefore, the kinetic energy of the body when it is thrown vertically upwards is 250 Joules (J).

To find the potential energy (PE) when the body reaches its highest point, we can use the formula for potential energy:

PE = m * g * h

where:
m = mass of the body (5 kg)
g = acceleration due to gravity (approximated as 9.8 m/s^2)
h = height above reference level (maximum height attained by the body)

Since the body is at its highest point, the height above the reference level would be the maximum height attained by the body. Therefore, we can use the given information to find the maximum height.

Using the equation for vertical motion:

v^2 = u^2 + 2 * a * s

where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (10 m/s)
a = acceleration due to gravity (-9.8 m/s^2, considering the downward direction as negative)
s = displacement (maximum height attained by the body)

Rearranging the equation:

0 = (10 m/s)^2 + 2 * (-9.8 m/s^2) * s
0 = 100 m^2/s^2 - 19.6 m/s^2 * s
19.6 m/s^2 * s = 100 m^2/s^2
s = (100 m^2/s^2) / 19.6 m/s^2
s ≈ 5.1 m

Therefore, the maximum height attained by the body is approximately 5.1 meters (m).

Now, to find the potential energy at the highest point:

PE = 5 kg * 9.8 m/s^2 * 5.1 m
≈ 249.9 kg * m^2/s^2

Therefore, the potential energy at the highest point is approximately 249.9 Joules (J).

To find the kinetic energy (KE) when the body is thrown, we can use the formula:

KE = (1/2)mv^2

Where m is the mass of the body and v is the velocity at which it is thrown.

In this case, the mass (m) is given as 5 kg, and the velocity (v) is given as 10 m/s.

Therefore, we can calculate the kinetic energy as follows:

KE = (1/2) * 5 kg * (10 m/s)^2
= (1/2) * 5 kg * 100 m^2/s^2
= 250 Joules

So, the kinetic energy of the body when it is thrown vertically upwards is 250 Joules.

To find the potential energy (PE) when the body reaches its highest point, we can use the formula:

PE = mgh

Where m is the mass of the body, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.

For the potential energy to be maximum, the height (h) is the maximum height attained by the body.

To find the maximum height, we need to use the conservation of energy. At the highest point, all the kinetic energy is converted into potential energy.

Therefore, we can equate the initial kinetic energy to the potential energy at the highest point:

KE = PE

Substituting the values we know, we have:

(1/2) * 5 kg * (10 m/s)^2 = 5 kg * 9.8 m/s^2 * h

Simplifying the equation:

250 Joules = 49 Joules/m * h
h = 250 Joules / 49 Joules/m
h ≈ 5.102 m

So, the maximum height attained by the body is approximately 5.102 meters.