posted by Sharma on .
a body of mass 5 kg is thrown vertically upwards with a speed of 10m/s what is its k.e. when it is thrown find its potential energy when it reaches at highest poiint also find maximum height attained by the body?
a. KE = 0.5m*Vo = 2.5*(10)^2 = 250 Joules
b. hmax = (Vf^2-Vo^2)/2g.
hmax = (0-(10)^2 / -19.6 = 5.10 m.
c. PE = mg*h = 5 * 9.8 * 5.1=250 Joules