Posted by kim on Friday, February 24, 2012 at 9:17pm.
solve by the substitution method. 6x+3y=21 4x+y=41

algebra  luther, Friday, February 24, 2012 at 10:49pm
there are so many ways of doing this problem! you can solve for x or y.
let's solve for x.
take 4x+y=41
when u solve x= 1/4y41/4
plug that value of x into the other equation: 6x+3y=21
it should look like this
6(1/4y41/4)+3y=21 and solve for y
after u solve for y
plug it in to whatever equation & solve for x and then u check it.
you can do it vice versa & solve for y first if you want too:)

algebra  Reiny, Friday, February 24, 2012 at 10:50pm
from the 2nd: y = 414x
sub into the 1st:
6x + 3y = 21
6x + 3(414x) = 21
6x +123  12x = 21
6x = 144
x = 24
sub into y = 414x = 414(24) = 55
x = 24
y = 55
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